Dennis Sweeney <sweeney.dennis...@gmail.com> added the comment:
This is just how local/nonlocal/global/builtin variables work in Python. When you assign to a name anywhere inside of a function, all occurrences of that name refer by default to a local variable. So the line "ZeroDivisionError = 1" tells the foo() function that it has some local variable called "ZeroDivisionError". In order to make sure that the ZeroDivisionError always refers to the builtin exception, you need to add a global statement: >>> def foo(): ... global ZeroDivisionError ... try: ... 1/0 ... except ZeroDivisionError as e: ... ZeroDivisionError = 1 >>> foo() >>> ZeroDivisionError 1 See also: https://docs.python.org/3/faq/programming.html?highlight=global#why-am-i-getting-an-unboundlocalerror-when-the-variable-has-a-value ---------- nosy: +Dennis Sweeney _______________________________________ Python tracker <rep...@bugs.python.org> <https://bugs.python.org/issue42632> _______________________________________ _______________________________________________ Python-bugs-list mailing list Unsubscribe: https://mail.python.org/mailman/options/python-bugs-list/archive%40mail-archive.com
