Mark Dickinson <dicki...@gmail.com> added the comment:

> As it currently stands, `a - (a*a > n)` is computed both in `isqrt` and 
> `isqrt_2`. So I was thinking that maybe the former might be dropped.

Ah, sorry; I misunderstood. Yes, I think so. I'll respond more fully later. 
(Sorry - real life getting in the way right now.)

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<https://bugs.python.org/issue43053>
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