Tim Peters <t...@python.org> added the comment:
Dennis, combinations("aaabbbcccddd") isn't a valid call - the function requires
a "how many?" argument too. If, e.g., we were asking for groups of 4, then
combinations("aaabbbcccddd", 4) generates the 4-tuple ('a', 'b', 'c', 'd') 81
(3**4) times, while the OP presumably only wants to get it once.
OTOH, combinations_with_replacement("abcd", 4) can generate tuples with more
than 3 repetitions of a given element.
The linked StackOverflow entry gives an efficient "real solution", but I agree
with its author's final comment: "It is much too specialized for itertools".
Indeed, it seems too obscure and special-purpose to me to even qualify as a
reasonable candidate for an itertools doc "recipe".
----------
nosy: +tim.peters
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<https://bugs.python.org/issue44197>
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