Andre Roberge <andre.robe...@gmail.com> added the comment:

Unless I am mistaken, when compiling the code, both SyntaxError and 
OverflowError instances are caught at the same stage, and likely passed on to 
showsyntaxerror.  For OverflowError, e.args is not normally a tuple but a 
string, and *e.args[1] would raise an exception.

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<https://bugs.python.org/issue43476>
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