Jason R. Coombs <[email protected]> added the comment:
Even simpler:
```
import zipfile
zip_file = zipfile.ZipFile('zipfile.zip')
names = [each.name for each in zipfile.Path(zip_file).iterdir()]
zip_file.open(names[0])
```
----------
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<https://bugs.python.org/issue44638>
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