New submission from mxmlnkn <maxinator...@googlemail.com>:
When using zipfile as a library to get simple files, there is no way to method to determine whether a ZipInfo object is a link or not. Moreover, links can be simply opened and read like normal files and will contain the link path, which is unexpected in most cases, I think. ZipInfo already has an `is_dir` getter. It would be nice if there also was an `is_link` getter. Note that `__repr__` actually shows the filemode, which is `lrwxrwxrwx`. But there is not even a getter for the file mode. For now, I can try to use the code from `__repl__` to extract the file mode from the `external_attr` member but the contents of that member are not documented in zipfile and assuming it is the same as in the ZIP file format specification, it's OS-dependent. Additionally to `is_link` some getter like `linkname` or so would be nice. As to how it should behave when calling `open` or `read` on a link, I'm not sure. ---------- messages: 402617 nosy: mxmlnkn priority: normal severity: normal status: open title: zipfile missing API for links _______________________________________ Python tracker <rep...@bugs.python.org> <https://bugs.python.org/issue45286> _______________________________________ _______________________________________________ Python-bugs-list mailing list Unsubscribe: https://mail.python.org/mailman/options/python-bugs-list/archive%40mail-archive.com
