Jan Novak <xnov...@users.sourceforge.net> added the comment:
I made some new tests in P2.6.1
>>> import email.charset
>>> c=email.charset.Charset('utf-8')
>>> print c.input_charset, type(c.input_charset)
utf-8 <type 'unicode'>
>>> print c.output_charset, type(c.output_charset)
utf-8 <type 'str'>
but
>>> c=email.charset.Charset('iso-8859-2')
>>> print c.input_charset, type(c.input_charset)
iso-8859-2 <type 'unicode'>
>>> print c.output_charset, type(c.output_charset)
iso-8859-2 <type 'unicode'>
but if you use alias latin-2 it's OK
>>> c=email.charset.Charset('latin-2')
>>> print c.input_charset, type(c.input_charset)
iso-8859-2 <type 'str'>
>>> print c.output_charset, type(c.output_charset)
iso-8859-2 <type 'str'>
>>>
Error is here for unicode input-charset:
self.input_charset->conv->self.output_charset
module email/charset.py line 219
if not conv:
conv = self.input_charset
for the charsets where aren't output conversions
CHARSETS = {
# input header enc body enc output conv
'iso-8859-1': (QP, QP, None),
'iso-8859-2': (QP, QP, None),
and if you don't use alias
ALIASES = {
'latin_1': 'iso-8859-1',
'latin-1': 'iso-8859-1',
'latin_2': 'iso-8859-2',
'latin-2': 'iso-8859-2',
But the realy source of this error is on line 208
input_charset = unicode(input_charset, 'ascii')
because this construction returns unicode
>>> print type(unicode('iso-8859-2','ascii'))
<type 'unicode'>
----------
title: email.Header encode() unicode P2.3xP2.4 -> email.Header encode() unicode
P2.6
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Python tracker <rep...@bugs.python.org>
<http://bugs.python.org/issue1379416>
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