New submission from Evgeniy Ivanov <a...@yandex.ru>:
Why operator 'pass' not implement to 'if-else' linear expression? Construction '<func/operation> if <expression> else pass' throws SyntaxError in Python 3.9 ---------- messages: 403793 nosy: evgnor86 priority: normal severity: normal status: open title: operator 'pass' in 'if-else' linear expression type: compile error versions: Python 3.6, Python 3.7, Python 3.8, Python 3.9 _______________________________________ Python tracker <rep...@bugs.python.org> <https://bugs.python.org/issue45456> _______________________________________ _______________________________________________ Python-bugs-list mailing list Unsubscribe: https://mail.python.org/mailman/options/python-bugs-list/archive%40mail-archive.com
