Jim Crist-Harif <jiminy.cr...@gmail.com> added the comment:
> Is there an OS interface to ensure the same port on both stacks? I don't think this is needed? Right now the code processes as: - Expand host + port + family + flags into a list of one or more tuples of socket options (https://github.com/python/cpython/blob/401272e6e660445d6556d5cd4db88ed4267a50b3/Lib/asyncio/base_events.py#L1432-L1436) - Iterate through this list, creating a new socket for each option tuple, and bind to the corresponding host + port (https://github.com/python/cpython/blob/401272e6e660445d6556d5cd4db88ed4267a50b3/Lib/asyncio/base_events.py#L1441-L1464) In this case, each call to `socket.bind` gets a 0 port, thus binding to a new random open port number each time. What I'm asking for is that if the user passes in `port=0`, then the port is extracted in the first call to `socket.bind` when looping and used for all subsequent `socket.bind` calls in the loop. This way we only ever choose a single random open port rather than 1 for each interface. FWIW, this is also what tornado does when `port=0` is provided. ---------- _______________________________________ Python tracker <rep...@bugs.python.org> <https://bugs.python.org/issue45693> _______________________________________ _______________________________________________ Python-bugs-list mailing list Unsubscribe: https://mail.python.org/mailman/options/python-bugs-list/archive%40mail-archive.com
