Eric V. Smith <e...@trueblade.com> added the comment:
problem_ary[:] creates a copy of problem_ary, so it's equal to: >>> problem_ary[:] [['a', 'b', 'c'], ['d', 'e', 'f'], ['g', 'h', 'i']] The [1] element of that is: >>> problem_ary[:][1] ['d', 'e', 'f'] So this is working as expected. I suggest you ask on StackOverflow or the python-list mailing list if you need more help in understanding how lists work in Python. ---------- nosy: +eric.smith resolution: -> not a bug stage: -> resolved status: open -> closed _______________________________________ Python tracker <rep...@bugs.python.org> <https://bugs.python.org/issue46093> _______________________________________ _______________________________________________ Python-bugs-list mailing list Unsubscribe: https://mail.python.org/mailman/options/python-bugs-list/archive%40mail-archive.com
