New submission from Jade Lovelace <softw...@lfcode.ca>: Currently the documentation for argparse.ArgumentParser states that the default value of the prog[ram] argument is argv[0], however, this does not match the actual behaviour of the constructor. In reality, the constructor uses the basename of argv[0], as can be seen in the code here: https://github.com/python/cpython/blob/e800dd1793dafbc4114da744f605731ff6630623/Lib/argparse.py#L1733-L1735
Here is a demo: /tmp » cat test.py import argparse ap = argparse.ArgumentParser() print(ap.prog) ap.print_usage() /tmp » python test.py test.py usage: test.py [-h] /tmp » python ./test.py test.py usage: test.py [-h] /tmp » mkdir test /tmp » cd test /tmp/test » python ../test.py test.py usage: test.py [-h] ---------- components: Library (Lib) files: test.py messages: 409515 nosy: lf- priority: normal pull_requests: 28549 severity: normal status: open title: argparse docs: default for prog= in ArgumentParser() should be basename of argv[0], not argv[0], to match behaviour type: enhancement versions: Python 3.10, Python 3.11, Python 3.6, Python 3.7, Python 3.8, Python 3.9 Added file: https://bugs.python.org/file50536/test.py _______________________________________ Python tracker <rep...@bugs.python.org> <https://bugs.python.org/issue46228> _______________________________________ _______________________________________________ Python-bugs-list mailing list Unsubscribe: https://mail.python.org/mailman/options/python-bugs-list/archive%40mail-archive.com
