Marek Scholle <mscho...@purestorage.com> added the comment:
I don't understand the comment https://bugs.python.org/issue46612#msg412374 ---- >>> def f(): x ... >>> f() ---- is OK, so x is something which can be evaluated inside nested function, it is a good target to be used in `x.__iadd__(iterable)`. That ---- >>> def f(): x = x + 1 ... >>> f() Traceback (most recent call last): File "<stdin>", line 1, in <module> File "<stdin>", line 1, in f UnboundLocalError: local variable 'x' referenced before assignment ---- is OK, the interpreter sees `x` as local variable (by default inner scope variables shadow those from outer scopes), hence the `UnboundLocalError` ---------- _______________________________________ Python tracker <rep...@bugs.python.org> <https://bugs.python.org/issue46612> _______________________________________ _______________________________________________ Python-bugs-list mailing list Unsubscribe: https://mail.python.org/mailman/options/python-bugs-list/archive%40mail-archive.com
