Serhiy Storchaka <storchaka+cpyt...@gmail.com> added the comment:
See the grammar. https://docs.python.org/3/reference/expressions.html#conditional-expressions conditional_expression ::= or_test ["if" or_test "else" expression] expression ::= conditional_expression | lambda_expr `*()` is not an expression. It is either a starred_item (which can be a part of starred_list or a starred_expression), or a positional_item or a starred_and_keywords which are parts of an argument_list. None of them are expressions. `foo(*(stri,) if stri else x)` is interpreted as `foo(*((stri,) if stri else x))` if x is an expression. But `*()` is not an expression, thus a syntax error. ---------- _______________________________________ Python tracker <rep...@bugs.python.org> <https://bugs.python.org/issue46865> _______________________________________ _______________________________________________ Python-bugs-list mailing list Unsubscribe: https://mail.python.org/mailman/options/python-bugs-list/archive%40mail-archive.com
