New submission from rive_n <rivenfornotificati...@gmail.com>:
Let's say we have default parser configuration: https://docs.python.org/3/library/argparse.html#other-utilities Like this one: ```python3 import argparse parser = argparse.ArgumentParser(prog='PROG') parser.add_argument('--foo', action='store_true', help='foo help') subparsers = parser.add_subparsers(help='sub-command help') # create the parser for the "a" command parser_a = subparsers.add_parser('a', help='a help') parser_a.add_argument('-a', help='bar help') # create the parser for the "b" command parser_b = subparsers.add_parser('b', help='b help') parser_b.add_argument('-b', help='baz help') ``` So i want to parse all subparsers arguments. For this purpose i could use `parse_known_args` method. But for some reason there is no way to get all of current args specified via command prompt or via list: `print(parser.parse_known_args(['a', '-a', '12', 'b', '-b', '32']))` - will not print 'a' and 'b' data. It will only contain first valid argument; This is pretty strange behavior. Why i can't just get all of actions (subparsers) ? ---------- components: Parser messages: 415412 nosy: lys.nikolaou, pablogsal, rive-n priority: normal severity: normal status: open title: Argparse can't parse subparsers with parse_known_args type: behavior versions: Python 3.8 _______________________________________ Python tracker <rep...@bugs.python.org> <https://bugs.python.org/issue47043> _______________________________________ _______________________________________________ Python-bugs-list mailing list Unsubscribe: https://mail.python.org/mailman/options/python-bugs-list/archive%40mail-archive.com
