STINNER Victor <vstin...@python.org> added the comment:
On my x86-64 Fedora 35, gcc says 32 bytes for sizeof(max_align_t). By the way,
g++ also says 32 bytes for sizeof(std::max_align_t).
GCC 11.2.1 defines max_align_t as:
---
#if (defined (__STDC_VERSION__) && __STDC_VERSION__ >= 201112L) \
|| (defined(__cplusplus) && __cplusplus >= 201103L)
#ifndef _GCC_MAX_ALIGN_T
#define _GCC_MAX_ALIGN_T
/* Type whose alignment is supported in every context and is at least
as great as that of any standard type not using alignment
specifiers. */
typedef struct {
long long __max_align_ll __attribute__((__aligned__(__alignof__(long long))));
long double __max_align_ld __attribute__((__aligned__(__alignof__(long
double))));
/* _Float128 is defined as a basic type, so max_align_t must be
sufficiently aligned for it. This code must work in C++, so we
use __float128 here; that is only available on some
architectures, but only on i386 is extra alignment needed for
__float128. */
#ifdef __i386__
__float128 __max_align_f128
__attribute__((__aligned__(__alignof(__float128))));
#endif
} max_align_t;
#endif
#endif /* C11 or C++11. */
---
file: /usr/lib/gcc/x86_64-redhat-linux/11/include/stddef.h
It's not an union but a structure with 2 fields (1 long long, 1 long double).
The __i386__ macro is not defined on Linux x86-64, so the struct does not have
the 3rd 128-bit float field.
align.c:
---
#include <stddef.h>
int main() { return sizeof(max_align_t); }
---
Build and run (C):
---
$ gcc align.c -o align && (./align; echo $?)
32
---
align.cpp:
---
int main() { return sizeof(std::max_align_t); }
---
Build and run (C++):
---
$ g++ align.cpp -o align && (./align; echo $?)
32
---
----------
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Python tracker <rep...@bugs.python.org>
<https://bugs.python.org/issue47179>
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