Florent Xicluna <la...@yahoo.fr> added the comment: You will prefer this one. It is as fast as the 2.7 version. The restrictions are described in the itertools documentation.
from itertools import count, takewhile irange = lambda start, stop, step: takewhile(lambda x: x<stop, (start+i*step for i in count())) >>> list(irange(-2**65,2**65,2**61)) [-36893488147419103232L, ... ---------- _______________________________________ Python tracker <rep...@bugs.python.org> <http://bugs.python.org/issue7721> _______________________________________ _______________________________________________ Python-bugs-list mailing list Unsubscribe: http://mail.python.org/mailman/options/python-bugs-list/archive%40mail-archive.com
