New submission from Virgil Dupras <hs...@hardcoded.net>: If we run 2to3 on the following code:
s = b' ' print s[0] == s we end up with this: s = b' ' print(s[0] == s) However, the first code, under python2 prints True while the converted code, under python3 prints False. Shouldn't 2to3 convert this code to: s = b' ' print s[0:1] == s instead? ---------- components: 2to3 (2.x to 3.0 conversion tool) messages: 108272 nosy: vdupras priority: normal severity: normal status: open title: 2to3 doesn't handle byte comparison well type: behavior versions: Python 2.7 _______________________________________ Python tracker <rep...@bugs.python.org> <http://bugs.python.org/issue9043> _______________________________________ _______________________________________________ Python-bugs-list mailing list Unsubscribe: http://mail.python.org/mailman/options/python-bugs-list/archive%40mail-archive.com
