Martin v. Löwis <mar...@v.loewis.de> added the comment: The change from issue1054943 is indeed bogus. As written, the code will happily run over starters, even though a blocked start means that subsequent characters can't possibly be combinable. That way, the code manages to combine, in 'Li\u030dt-s\u1e73\u0301', the final U+0301 with the i - even though there are several starters in-between.
I think the code should work like this: if comb!=0 and comb1==0: #starter after character with higher class: # not combinable, and all subsequent characters will be blocked # as well break if comb!=0 and comb1==comb: # blocked combining character, continue searching i1++ continue # candidate pair, check whether *i and *i1 are combinable It's unfortunate that the patch had been backported to 2.6.6; we can't fix it there anymore. ---------- _______________________________________ Python tracker <rep...@bugs.python.org> <http://bugs.python.org/issue10254> _______________________________________ _______________________________________________ Python-bugs-list mailing list Unsubscribe: http://mail.python.org/mailman/options/python-bugs-list/archive%40mail-archive.com
