Alex Willmer <a...@moreati.org.uk> added the comment: The re module throws an exception for re.compile(r'[\A\w]'). latest regex doesn't, but I don't think the pattern is matching correctly. Shouldn't findall(r'[\A]\w', 'a b c') return ['a'] and findall(r'[\A\s]\w', 'a b c') return ['a', ' b', ' c'] ?
Python 2.6.6 (r266:84292, Sep 15 2010, 16:22:56) [GCC 4.4.5] on linux2 Type "help", "copyright", "credits" or "license" for more information. >>> import re >>> for s in [r'\A\w', r'[\A]\w', r'[\A\s]\w']: print re.findall(s, 'a b c') ... ['a'] [] Traceback (most recent call last): File "<stdin>", line 1, in <module> File "/usr/lib/python2.6/re.py", line 177, in findall return _compile(pattern, flags).findall(string) File "/usr/lib/python2.6/re.py", line 245, in _compile raise error, v # invalid expression sre_constants.error: internal: unsupported set operator >>> import regex >>> for s in [r'\A\w', r'[\A]\w', r'[\A\s]\w']: print regex.findall(s, 'a b c') ... ['a'] [] [' b', ' c'] ---------- _______________________________________ Python tracker <rep...@bugs.python.org> <http://bugs.python.org/issue2636> _______________________________________ _______________________________________________ Python-bugs-list mailing list Unsubscribe: http://mail.python.org/mailman/options/python-bugs-list/archive%40mail-archive.com