On 8/31/05, Guido van Rossum <[EMAIL PROTECTED]> wrote: > > Hm. The example is poorly chosen because it's an end case. The > invariant for both is (I'd hope!) > > "".join(s.partition()) == s == "".join(s.rpartition())
<snip> > (Just think of it as rpartition() stopping at the last occurrence, > rather than searching from the right. :-) Ah, that makes a difference. I could see that there was a different way of looking at the function, I just couldn't see what it was... Now I understand the way it's been done. Cheers, Andrew. _______________________________________________ Python-Dev mailing list Python-Dev@python.org http://mail.python.org/mailman/listinfo/python-dev Unsubscribe: http://mail.python.org/mailman/options/python-dev/archive%40mail-archive.com
