I find myself in agreement with Inada (https://bugs.python.org/issue12445), in that comparing the values view between two dictionaries by itself would not be particularly useful for enough people to warrant implementing the comparison. In most situations when using the data structure, it is only useful to either compare the keys and values with ``d0.items() == d1.items()`` or just the keys with ``d0.keys() == d1.keys()``.
The values are generally not particularly useful without the corresponding keys, so I'm actually somewhat curious as to the motivation of creating the function ``dict.values()``. But, if for any reason someone actually had to compare only the values (I can't imagine the reason), they could compare them by converting them to a list: ``list(d0.values()) == list(d1.values())``. It adds an extra step, but I don't think enough people would make use of something like this to justify adding the direct comparison with ``d0.values() == d1.values())``. However, I agree that the current behavior of just returning ``False`` is quite misleading, regardless of whether or not implementing an accurate comparison between the values views would be worthwhile. I'm not sure as to what the most appropriate behavior would be, but since it's using ``__eq__``, [NotImplemented](https://docs.python.org/3/library/constants.html#NotImplemented) seems appropriate. Another alternative would be to return ``None``. A note in the docs for [NotImplementedError](https://docs.python.org/3/library/exceptions.html#NotImplementedError) states "It [NotImplementedError] should not be used to indicate that an operator or method is not meant to be supported at all – in that case either leave the operator / method undefined or, if a subclass, set it to None". _______________________________________________ Python-Dev mailing list -- python-dev@python.org To unsubscribe send an email to python-dev-le...@python.org https://mail.python.org/mailman3/lists/python-dev.python.org/ Message archived at https://mail.python.org/archives/list/python-dev@python.org/message/KX2TG7ZPVOWKUNDILV74YNFTBZTJHUP5/
