On Thu, 13 Jul 2006, Fredrik Lundh wrote: > Boris Borcic wrote: > > >> note that most examples of this type already work, if the target type is > >> mutable, and implement the right operations: > >> > >> def counter(num): > >> num = mutable_int(num) > >> def inc(): > >> num += 1 > >> return num > >> return inc [...] > feel free to replace that += with an .add(1) method call; the point > wasn't the behaviour of augmented assigment, the point was that that the > most common use pattern involves *mutation* of the target object.
I don't think that's clear. In: a = 1 b = a a += 1 it doesn't seem common to me that one would expect b to become 2. Sometimes you want mutation, sometimes you don't. I don't think that necessarily follows from whether you are accessing a free variable. -- ?!ng _______________________________________________ Python-Dev mailing list Python-Dev@python.org http://mail.python.org/mailman/listinfo/python-dev Unsubscribe: http://mail.python.org/mailman/options/python-dev/archive%40mail-archive.com