Leif Walsh wrote:
> On Tue, Feb 26, 2008 at 12:43 PM, Shaya Potter <[EMAIL PROTECTED]> wrote:
>> the -p <PASSWD> option is not good on multi user systems
>> the -p <PASSFILE> option is not particularly good on NFS based systems
>> (have to trust every user on every machine with access to NFS share)
>
> You seem somehow both worried about security, yet too lazy to type in
> your password. I think at some point, one of those concerns is going
> to have to give.
I want to run a program within a bash script, essentially daemonize a
program that doesn't have a daemon mode.
#!/bin/sh
echo "What Is Your Passsword: "
stty_orig=`stty -g`
stty -echo
read -r PASSWORD
stty $stty_orig
TIMEOUT=600
while [ 1 ]
do
echo $PASSWORD | program
sleep $TIMEOUT
done
>> and now, assuming what you say is part of the design behind the code
>>
>> what's the point of this part of the code
>>
>>
>> >> try:
>> >> fd = sys.stdin.fileno()
>> >> except:
>> >> return default_getpass(prompt)
>> >>
>>
>> i.e. the exception handler, default_getpass() is always going to read
>> from stdin at the end of the day.
>>
>> line = sys.stdin.readline()
>>
>> I'm assuming I'm missing something
>
> Sorry, I only know my way around the libc version of getpass(), not
> the python one. In that version, typically we try to open /dev/tty
> for reading, and if that fails, we fall back to stdin. I presume
> that's what's going on here, but the first line appears to be getting
> stdin anyway, so I'm no longer sure. That said, why don't you just
> use default_getpass() in your code, if it reads from stdin to begin
> with?
not my code, someone elses program, I can modify it, but that's a pain,
was mostly wondering if it could be changed at the python level (or at
least understand why python made the decision it did, sort of understand
the eating stdin aspect)
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