Paul Moore wrote:
2008/12/30 Phillip J. Eby <p...@telecommunity.com>:
You know, all this path separator and list complication isn't really
necessary, when you can just take the os.path.dirname() of the return from
commonprefix()....
Actually, consider: ...
os.path.commonprefix(["foo\\bar\\baz", "foo/bar/boink"])
'foo'
... I'm not sure how to deal with this, except by recommending that all
paths passed to os.path.commonprefix should at the very least be
normalised via os.path.normpath first - which starts to get clumsy
fast. So the "recommended" usage to get the common directory is
paths = [...]
common = os.path.dirname(os.path.commonprefix([
> os.path.normpath(p) for p in paths]))
More trouble with the "just take the dirname":
paths = ['/a/b/c', '/a/b/d', '/a/b']
os.path.dirname(os.path.commonprefix([
os.path.normpath(p) for p in paths]))
give '/a', not '/a/b'.
--Scott David Daniels
scott.dani...@acm.org
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