> That's simple clear and explicit: try_monotic() tries to use the
> monotic clock if it can, but falls back to time.time() rather than
> failing entirely if no monotonic clock is available.

I renamed time.steady() to time.try_monotonic() in the PEP. It's a
temporary name until we decide what to do with this function.

I also changed it to fallback to time.hires() if time.monotonic() is
not available or failed.

Victor
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