Stefan Behnel wrote:
This should work as long as this still creates a copy of d at some point:d = {...} dict(**d)
It will -- the implementation of the function call opcode always creates a new keyword dict for passing to the called function. -- Greg _______________________________________________ Python-Dev mailing list Python-Dev@python.org http://mail.python.org/mailman/listinfo/python-dev Unsubscribe: http://mail.python.org/mailman/options/python-dev/archive%40mail-archive.com
