Dear friends,
>>> from itertools import repeat
>>> list(repeat('a', 3))
['a', 'a', 'a']
>>> list(repeat('a', 0))
[]
>>> repeat.__doc__
'repeat(object [,times]) -> create an iterator which returns the
object\nfor the specified number of times. If not specified, returns
the object\nendlessly.'
If you omit the times argument:
>>> list(repeat('a'))
... unlimited of a .... sometimes it can hang your machine ....
In the C code it self, the default value of variable handling times
argument is -1. It checks how many arguments you give to the function.
So if you give -1 directly:
>>> list(repeat('a', -1))
[]
Negative value of times argument means 0.
So what is the correct signature of this function? The value is not
really capturable in Python and C.
repeat(object [,times = unlimited]) ????
Can we do this in Clinic? If not, should we?
Vajrasky
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