Is it intended that closures created in exec statement/function cannot see
locals if the exec was provided a locals dictionary?
This code gives an error ("foo" is not found during lambda execution):
exec("def foo(x): return x\n\n(lambda x:foo(x))(0)", globals(), {})
while executes normally with
exec("def foo(x): return x\n\n(lambda x:foo(x))(0)")
Is this the expected behavior? If so where is it documented?
Andrea
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