But the sort mutates F...does the setup get executed each time? I thought it's just at the beginning. So then F gets mutated (sorted) and subsequent sorts time wrong.
On Tue, Oct 11, 2016, 7:51 AM Paul Moore <p.f.mo...@gmail.com> wrote: > On 11 October 2016 at 14:04, Elliot Gorokhovsky > <elliot.gorokhov...@gmail.com> wrote: > > Right, that sounds good, but there's just one thing I don't understand > > that's keeping me from using it. Namely, I would define a benchmark list > L > > in my setup, and then I would have code="F=FastList(L);F.fastsort()". The > > problem here is I'm measuring the constructor time along with the sort > time, > > right, so wouldn't that mess up the benchmark? Or does timeit separate > the > > times? > > That would mess up your times. Put F=FastList(L) in your setup. > > Paul >
_______________________________________________ Python-Dev mailing list Python-Dev@python.org https://mail.python.org/mailman/listinfo/python-dev Unsubscribe: https://mail.python.org/mailman/options/python-dev/archive%40mail-archive.com
