Steven D'Aprano wrote:
t = (1, 2, 3) iterable = [t] [*t for t in iterable]If you do the same manual replacement, you get: [1, 2, 3 for t in iterable]
Um, no, you need to also *remove the for loop*, otherwise you get complete nonsense, whether * is used or not. Let's try a less degenerate example, both ways. iterable = [1, 2, 3] [t for t in iterable] To expand that, we replace t with each of the values generated by the loop and put commas between them: [1, 2, 3] Now with the star: iterable = [(1, 2, 3), (4, 5, 6), (7, 8, 9)] [*t for t in iterable] Replace *t with each of the sequence generated by the loop, with commas between: [1,2,3 , 4,5,6 , 7,8,9]
Maybe your inability to look past your assumptions and see things from other people's perspective is just as much a blind spot as our inability to see why you think the pattern is obvious.
It's obvious that you're having difficulty seeing what we're seeing, but I don't know how to explain it any more clearly, I'm sorry. -- Greg _______________________________________________ Python-ideas mailing list Python-ideas@python.org https://mail.python.org/mailman/listinfo/python-ideas Code of Conduct: http://python.org/psf/codeofconduct/
