It's in the code. See longobject.c: Py_SIZE(v) = ndigits*sign;
You can also see Py_SIZE(v) used on PyLongs all over the place in longobject.c, for example: v = (PyLongObject *)vv; i = Py_SIZE(v); Just do a ctrl-f for Py_SIZE(v) in longobject.c. Like I said, by looking in the implementation I was able to figure out that Py_SIZE is interpreted as the sign times the number of digits (unless I'm missing something), but this should be in the docs IMO. On Wed, Oct 19, 2016 at 7:24 PM Thomas Nyberg <tomuxi...@gmx.com> wrote: > On 10/19/2016 09:04 PM, Elliot Gorokhovsky wrote: > > A quick note: > > > > I'm working on a special-case compare function for bounded integers for > > the sort stuff. By looking at the implementation, I figured out that > > Py_SIZE of a long is the sign times the number of digits (...right?). > > Before looking at the implementation, though, I had looked for this info > > in the docs, and I couldn't find it anywhere. Since Py_SIZE is public, I > > think the documentation should make clear what it returns for PyLongs, > > for example somewhere on the "Integer Objects" page. Apologies if this > > is specified somewhere else in the docs and I just couldn't find it. > > > > Elliot > > I don't think this is right. > > > https://github.com/python/cpython/blob/master/Include/object.h#L119 > https://docs.python.org/3/c-api/structures.html#c.Py_SIZE > https://docs.python.org/3/c-api/structures.html#c.PyVarObject > > It returns the `ob_size` fields of a PyVarObject. I think this has to do > with objects with variable sizes like lists. PyLongs are not > PyVarObjects because they have no notion of length. > > Why would a long be stored as a sequence of digits instead of a (say) 64 > bit integer as 8 bytes? > > Cheers, > Thomas > > _______________________________________________ > Python-ideas mailing list > Python-ideas@python.org > https://mail.python.org/mailman/listinfo/python-ideas > Code of Conduct: http://python.org/psf/codeofconduct/ >
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