Hi everyone,
Here is a simplification of a problem that's been happening in my code:
import contextlib
@contextlib.contextmanager
def f():
print('1')
try:
yield
finally:
print('2')
g = f()
g.__enter__()
This code prints 1 and then 2, not just 1 like you might expect. This is
because when the generator is garbage-collected, it gets `GeneratorExit`
sent to it.
This has been a problem in my code since in some instances, I tell a
context manager not to do its `__exit__` function. (I do this by using
`ExitStack.pop_all()`. However the `__exit__` is still called here.
I worked around this problem by adding `except GeneratorExit: raise` in my
context manager, but that's an ugly solution.
Do you think that something could be done so I won't have to add `except
GeneratorExit: raise` to each context manager to get the desired behavior?
Thanks,
Ram.
_______________________________________________
Python-ideas mailing list
[email protected]
https://mail.python.org/mailman/listinfo/python-ideas
Code of Conduct: http://python.org/psf/codeofconduct/
