On 15.05.17 18:46, Ryan Gonzalez wrote:
I guess maybe if you overload the operators to return broken objects, maybe then they would be different?
No. The compiler generates an equivalent bytecode for both cases. _______________________________________________ Python-ideas mailing list Python-ideas@python.org https://mail.python.org/mailman/listinfo/python-ideas Code of Conduct: http://python.org/psf/codeofconduct/