>>> a = [1,2,3]
>>> [x if x & 1 else 'even' for x in a]
[1, 'even', 3]
You're mixing the if clause of the list comprehension up with a
ternary expresssion. There's no "else" in the list comprehension if
clause.
Paul
On 5 October 2017 at 16:40, Jason H <jh...@gmx.com> wrote:
>>>> a = [1,2,3]
>>>> [ x for x in a if x & 1]
> [1, 3]
>>>> [ x for x in a if x & 1 else 'even']
> File "<stdin>", line 1
> [ x for x in a if x & 1 else 'even']
> ^
> SyntaxError: invalid syntax
>
> I expected [1, 'even', 3]
>
> I would expect that the if expression would be able to provide alternative
> values through else.
>
> The work around blows it out to:
> l = []
> for x in a:
> if x&1:
> l.append(x)
> else:
> l.append('even')
>
>
> Unless there is a better way?
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