On 2018-04-29 04:17 PM, Nikolaus Rath wrote:
On Apr 27 2018, Tim Peters <tim.peters-re5jqeeqqe8avxtiumw...@public.gmane.org>
wrote:
Then `c` is 12, but `a` is still 1 and `b` is still 2. Same thing in the end:
c = local(a=3, b=4, a*b)
I think this can be done already with slighly different syntax:
c = (lambda a=3, b=4: a*b)()
The trailing () is a little ugly, but the semantics are much more
obvious. So maybe go with a variation that makes function evaluation
implicit?
c = lambda! a=3, b=4: a*b
(reads terrible, but maybe someone has a better idea).
if local(m = re.match(regexp, line)):
print(m.group(0))
Of course, that wouldn't (and shouldn't) work anymore. But that's a good
thing, IMO :-).
Best,
-Nikolaus
Has anyone heard of Lua? Lexical scoping? Block scope? (Python doesn't
have blocks and that sucks?) Etc?
_______________________________________________
Python-ideas mailing list
Python-ideas@python.org
https://mail.python.org/mailman/listinfo/python-ideas
Code of Conduct: http://python.org/psf/codeofconduct/
