Steve and Johnathan, it seems like we're on the same page. Currently, is <expr1> = <expr2> = <expr3> = <expr4> always equivalent to <expr1> = <expr4>; <expr2> = <expr4>; <expr3> = <expr4>?
When there are a tuple or list of names on the left hand side (ex. `a, b` or `(a, b)` or `[a, b]`), unpack the right hand side into values and perform the augmented assignment on each name on the left hand side. Borrowing Johnathan's example: a = b = 0 incr = (1, 2) a, b += incr # now (a, b) == (1, 2) concat = (-1, 0) concat += incr # existing behavior: now concat == (1, 2, 3, 4) Like Steve said, you can save vertical space and avoid creating temporary variables: temp_a, temp_b = simulate(new_deck) tally_a += temp_a tally_b += temp_b tally_a, tally_b = simulate(new_deck )
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