I think it could inherit from the Mapping abc?
class frozendict(Mapping):
def __new__(cls, *args, **kwargs):
d = dict(*args, **kwargs)
proxy = MappingProxyType(d)
instance = super().__new__(cls)
instance.__proxy = proxy
return instance
def __hash__(self):
return hash(tuple(self.items()))
def __getattr__(self, name):
return getattr(self.__proxy, name)
def __getitem__(self, key):
return self.__proxy[key]
def __iter__(self):
return self.__proxy.__iter__()
def __len__(self):
return len(self.__proxy)
def __repr__(self):
return "%s(%r)" % (type(self).__name__, dict(self))
On Tue, Oct 16, 2018 at 4:29 AM Steven D'Aprano <[email protected]> wrote:
> On Tue, Oct 16, 2018 at 01:02:03AM -0700, George Leslie-Waksman wrote:
> > Would a frozendict require that keys and values be hashable?
>
> Keys, yes. Values, no.
>
> If the values were hashable, the frozendict itself would also be
> hashable. If not, then it would be like trying to hash a tuple with
> unhashable items:
>
> py> hash((1, 2, {}, 3))
> Traceback (most recent call last):
> File "<stdin>", line 1, in <module>
> TypeError: unhashable type: 'dict'
>
>
> > It seems to me that we would need this restriction to make a reasonably
> > universal frozendict that is, itself, hashable.
>
> When people talk about frozendicts being hashable, they mean it in the
> same sense that tuples are hashable.
>
>
> For what it is worth, here's an incomplete, quick and dirty proof of
> concept frozendict, using automatic delegation:
>
> # Not good enough for production, not tested, buyer beware, etc.
> class frozendict:
> def __new__(cls, *args, **kwargs):
> d = dict(*args, **kwargs)
> proxy = types.MappingProxyType(d)
> instance = super().__new__(cls)
> instance.__proxy = proxy
> return instance
> def __hash__(self):
> return hash(tuple(self.items()))
> def __getattr__(self, name):
> return getattr(self.__proxy, name)
> def __getitem__(self, key):
> return self.__proxy[key]
> def __repr__(self):
> return "%s(%r)" % (type(self).__name__, dict(self))
>
>
> --
> Steve
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