Does it make sense to draw some sort of parallel between next(myiterator, default="whatever") and mylist.pop(default="whatever")? They exhaust the iterator/list then start emitting the default argument (if provided).
On Thu, Nov 1, 2018 at 2:46 PM Serhiy Storchaka <storch...@gmail.com> wrote: > 31.10.18 13:08, Antoine Pitrou пише: > > +1 from me. dict.pop() already has an optional default. This is a > > straight-forward improvement to the API and no Python programmer will > > be surprised. > > list.pop() corresponds two dict methods. With argument it corresponds > dict.pop(). But there are differences: dict.pop() called repeatedly with > the same key will raise an error (or return the default), while > list.pop() will likely return other item. Without argument it > corresponds dict.popitem() which doesn't have an optional default. > > _______________________________________________ > Python-ideas mailing list > Python-ideas@python.org > https://mail.python.org/mailman/listinfo/python-ideas > Code of Conduct: http://python.org/psf/codeofconduct/ >
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