On Fri, Apr 12, 2019 at 11:10 AM Viktor Roytman <viktor.royt...@gmail.com>
wrote:
>
> The standard approach I have encountered in this scenario is to pass in
> the keyword arguments explicitly like so
>
> func(
> a=kwargs_dict["a"],
> b=kwargs_dict["b"],
> c=kwargs_dict["c"],
> )
>
func(**{k:v for k, v in d.items() if k in ('a','b','c'))
Or you can `def dict_filter(d, yes)` to the the above.
--
Juancarlo *Añez*
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