On Thu, Dec 05, 2019 at 05:40:05PM -0400, Juancarlo Añez wrote:
> I just found this code:
>
> def get_product_item(jsonld_items):
> for item in jsonld_items:
> if item['@type'] == 'Product':
> return item
> else:
> return {}
I'm sorry, I can't tell what that is supposed to do. Is the "return {}"
supposed to be inside the loop? If so, it has been accidentally
dedented. Is it meant to be outside the loop? The "for-else" is
redundent, since there is no break.
for item in jsonld_items:
if item['@type'] == 'Product':
return item
else: # Even this "else" is redundent too.
return {}
for item in jsonld_items:
if item['@type'] == 'Product':
return item
# else is unnecessary here
return {}
The name says it returns an item, but the default is to return an empty
dict, which seems like an unusual choice for the "default product where
no product is specified". I would have guessed None if the product is
missing.
> My argument is that the intent is clearer in:
>
> def get_product_item(jsonld_items):
> return first((item for item in jsonld_items if item['@type'] ==
> 'Product'), {})
That's certainly an improvement, but the helper function "first" is
redundant. You can just write:
return next((item for item in jsonld_items if item['@type'] ==
'Product'), default={})
What's the benefit of adding a new builtin which is essentially just a
thin do-almost-nothing wrapper around `next`? Have I missed something?
--
Steven
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