10.04.20 23:21, Elliott Dehnbostel пише:
If I've done this incorrectly, please let me know so that I can
improve/revise. I'm new to the Python community and quite enjoy the more
functional features of Python 3, but have I have a peeve about it. I'd
like to propose and discuss the following enhancement to Python 3:
*
Consider the following trivial for-loop:*
chars= "abcaaabkjzhbjacvb"
seek= {'a','b','c'}
count= 0
for ain chars:
if ain seek:
count+= 1
Gross. Twice nested for a simple count.
/We could refactor the block like so:/
Don't listen to anyone. There is only one obvious way to write this in
one line:
count = +(lambda *a: a[0](*a))((lambda q, r, s, i: r(r, q, s, i, next(i,
s))), (lambda r, q, s, i, x: x is not s and (x in seek) + q(q, r, s,
i)), [], iter(chars))
It is not even use such non-functional paradigm as a for loop.
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