You can get the desired behavior by casting a list to a tuple, or a tuple
to a list, in the equality statement. That way those that rely on the
existing implementation don't have to change their code.
my_tup = (1, 2, 3)
my_list = [1, 2, 3]
print(list(my_tup) == my_list)
On Sat, May 2, 2020, 9:04 AM Ahmed Amr <ahmedam...@gmail.com> wrote:
> I'd like to take your opinion on modifying some of the indexed collections
> like tuples, lists, arrays to evaluate its equality to True when having the
> same items in the same indexes.
> Currently, when comparing a list of items to an array of the same items
> for equality (==) it returns False, I'm thinking that it would make sense
> to return True in that context, as we're comparing item values and we have
> the same way of indexing both collections, so we can compare item values.
>
> So what do you think about applying such behavior on collections that can
> be indexed the same way such as tuples, lists, and arrays?
>
> Example: (Current)
>
> import array
> tuple_ = (1.1, 2.2, 3.3)
> list_ = [1.1, 2.2, 3.3]
> array_ = array.array('f', [1.1, 2.2, 3.3])
>
> # all of the following prints False.
> print(tuple_ == list_)
> print(tuple_ == array_)
> print(array_ == list_)
>
> Example: (Proposed):
> All prints above to show True as they are populated with the same data in
> the same indexes.
>
> A Side Note:
> An extra point to discuss, based on arrays implementation,
> array_.to_list() would actually get [1.100000023841858, 2.200000047683716,
> 3.299999952316284] which is not exactly what we've passed as args and this
> is normal, but I'm thinking about leaving it to the array implementation to
> encapsulate that implementation and perform exact equality based on passed
> arguments.
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