I agree that calling random.shuffle imperatively is annoying. But I don't
think your proposed solution is readable. You're not taking a sample. A
sample generally implies a strict subset, usually quite a small one.

I've often thought there should just be a `random.shuffled()` function
which returns a shuffled copy, similar to `.sort()` and `sorted()` or
`.reverse()` and `reversed()`.

On Sat, Aug 1, 2020 at 7:59 PM Ram Rachum <r...@rachum.com> wrote:

> When writing some code now, I needed to produce a shuffled version of
> `range(10, 10 ** 5)`.
>
> This is one way to do it:
>
> shuffled_numbers = list(range(10, 10 ** 5))
> random.shuffle(shuffled_numbers)
>
>
> I don't like it because (1) it's too imperative and (2) I'm calling the
> list "shuffled" even before it's shuffled.
>
> Another solution is this:
>
> shuffled_numbers = random.sample(range(10, 10 ** 5), k=len(range(10, 10 **
> 5)))
>
> This is better because it solves the 2 points above. However, it is quite
> cumbersome.
>
> I notice that the `random.sample` function doesn't have a default behavior
> set when you don't specify `k`. This is fortunate, because we could make
> that behavior just automatically take the length of the first argument. So
> we could do this:
>
> shuffled_numbers = random.sample(range(10, 10 ** 5))
>
> What do you think?
>
>
> Thanks,
> Ram.
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