Hi,
Python supports IPv4-mapped IPv6 addresses as defined by RFC 4038:
"the IPv6 address ::FFFF:x.y.z.w represents the IPv4 address x.y.z.w.”
The current behavior is as follows:
from ipaddress import ip_address
addr = ip_address('::ffff:8.8.4.4') # IPv6Address('::ffff:808:404')
addr.ipv4_mapped # IPv4Address('8.8.4.4')
Note that the textual representation of the IPv6Address is *not* in IPv4-mapped
format.
It prints ::ffff:808:404 instead of ::ffff:8.8.4.4.
This is technically correct, but it’s somewhat frustrating as it makes it
harder to read IPv4s embedded in IPv6 addresses.
My proposal would be to check, in __str__, if an IPv6 is an IPv4-mapped, and to
return the appropriate representation :
from ipaddress import ip_address
addr = ip_address('::ffff:8.8.4.4')
# Current behavior
str(addr) # '::ffff:808:404'
repr(addr) # IPv6Address('::ffff:808:404')
# Proposed behavior
str(addr) # '::ffff:8.8.4.4'
repr(addr) # IPv6Address('::ffff:8.8.4.4')
A few data points:
- Julia prints ::ffff:808:404 (current behavior)
- C (glibc) and ClickHouse prints ::ffff:8.8.4.4 (proposed behavior)
Any thoughts?
Maxime
_______________________________________________
Python-ideas mailing list -- [email protected]
To unsubscribe send an email to [email protected]
https://mail.python.org/mailman3/lists/python-ideas.python.org/
Message archived at
https://mail.python.org/archives/list/[email protected]/message/T7FN2PMPNY5E5234ZNL4BAEYVJFKPE4U/
Code of Conduct: http://python.org/psf/codeofconduct/
