On Thu, Jun 17, 2021 at 4:07 PM Guido van Rossum <gu...@python.org> wrote:
>
> Just trolling along, flattening a list could be written as
>
> functools.reduce(list.__iadd__, xs, [])
>
> Right?
>

Insufficiently trolly - lacks walrus operator. :)

>>> l = [[1,2],[3,4],[5,6],[7,8],[9]]
>>> any(map((x:=[]).extend, l)) or x
[1, 2, 3, 4, 5, 6, 7, 8, 9]

ChrisA
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