> On 14 Oct 2021, at 12:21 PM, Steven D'Aprano <st...@pearwood.info> wrote:
>
>
> Why abbreviate list and tuple but not string?
>
Empty strings would be confusing as a type unless you mean a Literal empty
string. We just limit the picture of the type to lists, tuples, dicts, and
sets. Builtin most often used collections. Imagine you have a default parameter
like this... name: “” = “”. This adds unnecessary confusion.
> Not really. Your first example is explicit and I can get the meaning by
> just reading it out loud:
>
> tuple[list[list[str]], list[list[str]]]
>
> "tuple (of) list (of) list (of) str, list (of) list (of) str
>
> Your abbreviated version:
>
> ([[str]], [[str]])
>
> is too terse. I have to stop and think about what it means, not just
> read it out loud. Without the hint of named types (tuple and list), my
> first reaction to seeing [str] is "is this an optional string?".
I am a visual guy. ([[str]], [[str]]) is much easier to my eyes than reading
tuple (of) list (of) list (of) str, list (of) list (of) str.
> don't look like "optional" to me
Optional would be Optional[str] or str | None, not [str].
> No, because the # indicates that the rest of the line is a comment. This
> is already legal:
>
> def func(d: {str # this is an actual comment
> : int}) -> Any: ...
>
> so this would be ambiguous between a real comment and an annotation.
>
> Even if we agreed to change the behaviour of comments, you suggested:
>
> func(d: {str # product label: [float] # prices from 2000 to 2015})
>
> How is the interpreter to know that the first annotation is just
>
> "product label"
>
> rather than this?
>
> "product label: [float] # prices from 2000 to 2015"
>
> So I don't think this works.
>
# is not a good idea I agree. How about the following for Annotated:
func(d: {str & "product label": [float] & "prices from 2000 to 2015"})?
The “&” is similar to “& co.” (and company). They come together but the first
one is the group leader and represents all of them. It works in an opposite way
to “|” (or), which gives importance equally to the members.
def func(
time: float & “hours” & datetime.timedelta.total_seconds()/3600,
verbose: bool & “option for long text” = False,
) -> str: …
Abdulla
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