On Sat, Oct 23, 2021, 11:46 PM David Mertz, Ph.D.
> def f(x=defer: a + b):
>> a, b = 3, 5
>> return x
>>
>> Would this return 8, or a defer-expression? If 8, then the scope isn't
>> truly dynamic, since there's no way to keep it deferred until it moves to
>> another scope. If not 8, then I'm not sure how you'd define the scope or
>> what triggers its evaluation.
>
>
Oh... Keep in mind I'm proposing a strawman deliberately, but the most
natural approach to keeping an object deferred rather than evaluated is
simply to say so:
def f(x=defer: a + b):
a, b = 3, 5
fn2(defer: x) # look for local a, b within fn2() if needed
# ... other stuff
return x # return 8 here
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