In case you're actually using an array of numbers, and not a general list, you can use numpy to do it 'the matlab way':
>>> import numpy >>> arr = numpy.array([1,2,3,4,5,6]) >>> arr array([1, 2, 3, 4, 5, 6]) >>> arr[[0,5,-1]] array([1, 6, 6]) - Sagiv On Thu, Dec 30, 2010 at 12:55 AM, Rani Hod <[email protected]> wrote: > Unlike Perl, Python is based upon the principle of having exactly one >> way to do each thing. >> List comprehension (the [arr[x] for x in [1,6,9] ] method) is one way to >> accomplish the goal, and it is reasonably parsimonious. Therefore, it >> is very unlikely to have another method of accomplishing the same. >> > > There is another method, but I wouldn't call it elegant. > It ought to be more efficient, though. > > map(arr.__getitem__, (1,6,9)) > > _______________________________________________ > Python-il mailing list > [email protected] > http://hamakor.org.il/cgi-bin/mailman/listinfo/python-il > >
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