Hi,
How can I STOP Optionparse to process boolean value as parameter. See this:
>>> parser = optparse.OptionParser()
>>> parser.add_option("-x",dest='xxx', action="store_true",help="xxx")
>>> parser.add_option("-r",dest='root',help="directory",type="string")
>>> args = ["-r", "d:", "-x"]
>>> parser.parse_args(args)
(<Values at 0x13bbbc0: {'xxx': True, 'root': 'd:'}>, [])Last line is correct: boolean 'xxx' gets set 'True' and parameter 'root' to 'd:'
However when value is NOT given for '-r' but '-x' exists:
>>> args = ["-r", "-x"]
>>> parser.parse_args(args)
(<Values at 0x13ccf80: {'xxx': None, 'root': '-x'}>, [])This is BS: I expected 'root' to be None and 'xxx' to be 'True'. How can I make it so?
Another question: Is there a way to store options directly into user defined dictionary without assignment like this:
my_environment_values = {}
(options, args) = parser.parse_args()
environment_values["xxx"] = options.xxx-pekka- -- http://mail.python.org/mailman/listinfo/python-list
