Hello Nick,
thank you, your answer really helped me..
-- Greg
Nick Coghlan wrote:
Gregor Horvath wrote:
Hello,
class A(self): def A1(): pass
class B(self): def B1(): #************************************ #*** How can I access A1 here???? *** #************************************ self.A1() # doesnet work because self references to B self.self.A1() #doesnt work either
Renanimg class B(self1): doesnt work either because self is not bound.
OK, I suspect you're a little confused about how classes work. The items in brackets after a class name are the *base* classes of a class, not the way the class refers to itself. So Python will complain if the listed items can't be inherited from for one reason or another.
I suggest having another read of the tutorial section on classes to figure out exactly what you want to be doing:
http://www.python.org/doc/2.3.4/tut/node11.html
How can I access a method of a "upper" class?
Merely defining one class inside another class does not automatically give instances of that inner class a reference to an instance of the outer class - if such a reference is needed, it must be provided in the inner class's constructor.
E.g.
class A(object): class B(object): def __init__(self, owner): self._owner = owner
def B1(self): self._owner.A1()
def A1(self): pass
def makeB(self): return A.B(self)
Cheers, Nick.
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